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13134332401 is a prime number
BaseRepresentation
bin11000011101101111…
…00000000111110001
31020220100120012212121
430032313200013301
5203344342114101
610011150154241
7643323661201
oct141667400761
936810505777
1013134332401
11562aa96373
1226667b2981
131314176428
148c8536401
1551d1390a1
hex30ede01f1

13134332401 has 2 divisors, whose sum is σ = 13134332402. Its totient is φ = 13134332400.

The previous prime is 13134332347. The next prime is 13134332489. The reversal of 13134332401 is 10423343131.

13134332401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12133242801 + 1001089600 = 110151^2 + 31640^2 .

It is a cyclic number.

It is not a de Polignac number, because 13134332401 - 231 = 10986848753 is a prime.

It is not a weakly prime, because it can be changed into another prime (13134330401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567166200 + 6567166201.

It is an arithmetic number, because the mean of its divisors is an integer number (6567166201).

Almost surely, 213134332401 is an apocalyptic number.

It is an amenable number.

13134332401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13134332401 is an equidigital number, since it uses as much as digits as its factorization.

13134332401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13134332401 its reverse (10423343131), we get a palindrome (23557675532).

The spelling of 13134332401 in words is "thirteen billion, one hundred thirty-four million, three hundred thirty-two thousand, four hundred one".