Base | Representation |
---|---|
bin | 10011000111001110101… |
… | …110111101111100000101 |
3 | 11122120012102202010012212 |
4 | 103013032232331330011 |
5 | 133004402430202401 |
6 | 2443214420553205 |
7 | 163615051032422 |
oct | 23071656757405 |
9 | 4576172663185 |
10 | 1313433444101 |
11 | 467029a35609 |
12 | 192676252805 |
13 | 96b1921a22c |
14 | 477db702d49 |
15 | 24273444dbb |
hex | 131cebbdf05 |
1313433444101 has 2 divisors, whose sum is σ = 1313433444102. Its totient is φ = 1313433444100.
The previous prime is 1313433444053. The next prime is 1313433444269. The reversal of 1313433444101 is 1014443343131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1047460137025 + 265973307076 = 1023455^2 + 515726^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313433444101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313433444601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656716722050 + 656716722051.
It is an arithmetic number, because the mean of its divisors is an integer number (656716722051).
Almost surely, 21313433444101 is an apocalyptic number.
It is an amenable number.
1313433444101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313433444101 is an equidigital number, since it uses as much as digits as its factorization.
1313433444101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 1313433444101 its reverse (1014443343131), we get a palindrome (2327876787232).
The spelling of 1313433444101 in words is "one trillion, three hundred thirteen billion, four hundred thirty-three million, four hundred forty-four thousand, one hundred one".
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