131344010013011 has 4 divisors (see below), whose sum is σ = 131344137180192. Its totient is φ = 131343882845832.

The previous prime is 131344010012987. The next prime is 131344010013089. The reversal of 131344010013011 is 110310010443131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131344010013011 - 2¹⁴ = 131344009996627 is a prime.

It is a super-2 number, since 2×131344010013011² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131344010013311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62021531 + ... + 64104276.

It is an arithmetic number, because the mean of its divisors is an integer number (32836034295048).

Almost surely, 2^{131344010013011} is an apocalyptic number.

131344010013011 is a deficient number, since it is larger than the sum of its proper divisors (127167181).

131344010013011 is a wasteful number, since it uses less digits than its factorization.

131344010013011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127167180.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 131344010013011 its reverse (110310010443131), we get a palindrome (241654020456142).

The spelling of 131344010013011 in words is "one hundred thirty-one trillion, three hundred forty-four billion, ten million, thirteen thousand, eleven".