Base | Representation |
---|---|
bin | 11000011101101111… |
… | …10011000100001101 |
3 | 1020220100201011022112 |
4 | 30032313303010031 |
5 | 203344402104442 |
6 | 10011151553405 |
7 | 643324433342 |
oct | 141667630415 |
9 | 36810634275 |
10 | 13134409997 |
11 | 56300396a5 |
12 | 266682b865 |
13 | 13141a2847 |
14 | 8c85567c9 |
15 | 51d152082 |
hex | 30edf310d |
13134409997 has 2 divisors, whose sum is σ = 13134409998. Its totient is φ = 13134409996.
The previous prime is 13134409993. The next prime is 13134410053. The reversal of 13134409997 is 79990443131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12979133476 + 155276521 = 113926^2 + 12461^2 .
It is an emirp because it is prime and its reverse (79990443131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13134409997 - 22 = 13134409993 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13134409993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6567204998 + 6567204999.
It is an arithmetic number, because the mean of its divisors is an integer number (6567204999).
Almost surely, 213134409997 is an apocalyptic number.
It is an amenable number.
13134409997 is a deficient number, since it is larger than the sum of its proper divisors (1).
13134409997 is an equidigital number, since it uses as much as digits as its factorization.
13134409997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 734832, while the sum is 50.
The spelling of 13134409997 in words is "thirteen billion, one hundred thirty-four million, four hundred nine thousand, nine hundred ninety-seven".
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