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1313441433353 = 7187634490479
BaseRepresentation
bin10011000111001111001…
…101011100011100001001
311122120012222210000102002
4103013033031130130021
5133004412001331403
62443215304120345
7163615205655620
oct23071715343411
94576188700362
101313441433353
114670334a1aa5
12192678a660b5
1396b1aa867ba
14477dc7c26b7
1524273ec2188
hex131cf35c709

1313441433353 has 4 divisors (see below), whose sum is σ = 1501075923840. Its totient is φ = 1125806942868.

The previous prime is 1313441433349. The next prime is 1313441433377. The reversal of 1313441433353 is 3533341443131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313441433353 - 22 = 1313441433349 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313441433323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93817245233 + ... + 93817245246.

It is an arithmetic number, because the mean of its divisors is an integer number (375268980960).

Almost surely, 21313441433353 is an apocalyptic number.

It is an amenable number.

1313441433353 is a deficient number, since it is larger than the sum of its proper divisors (187634490487).

1313441433353 is an equidigital number, since it uses as much as digits as its factorization.

1313441433353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187634490486.

The product of its digits is 233280, while the sum is 38.

Adding to 1313441433353 its reverse (3533341443131), we get a palindrome (4846782876484).

The spelling of 1313441433353 in words is "one trillion, three hundred thirteen billion, four hundred forty-one million, four hundred thirty-three thousand, three hundred fifty-three".

Divisors: 1 7 187634490479 1313441433353