Base | Representation |
---|---|
bin | 11101110111010011111010… |
… | …011110001111011101101110 |
3 | 122020001101121020122210200202 |
4 | 131313103322132033131232 |
5 | 114203421112322041332 |
6 | 1143202423414153502 |
7 | 36444212151325001 |
oct | 3567237236173556 |
9 | 566041536583622 |
10 | 131344302143342 |
11 | 3893989546a422 |
12 | 128934a5052892 |
13 | 5839939b21b12 |
14 | 2461153439538 |
15 | 102b877a0ea62 |
hex | 7774fa78f76e |
131344302143342 has 4 divisors (see below), whose sum is σ = 197016453215016. Its totient is φ = 65672151071670.
The previous prime is 131344302143321. The next prime is 131344302143359. The reversal of 131344302143342 is 243341203443131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1313443021433422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131344302143296 and 131344302143305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32836075535834 + ... + 32836075535837.
It is an arithmetic number, because the mean of its divisors is an integer number (49254113303754).
Almost surely, 2131344302143342 is an apocalyptic number.
131344302143342 is a deficient number, since it is larger than the sum of its proper divisors (65672151071674).
131344302143342 is an equidigital number, since it uses as much as digits as its factorization.
131344302143342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65672151071673.
The product of its (nonzero) digits is 248832, while the sum is 38.
Adding to 131344302143342 its reverse (243341203443131), we get a palindrome (374685505586473).
The spelling of 131344302143342 in words is "one hundred thirty-one trillion, three hundred forty-four billion, three hundred two million, one hundred forty-three thousand, three hundred forty-two".
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