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13134432011 = 48172726683
BaseRepresentation
bin11000011101101111…
…11000011100001011
31020220100202021111212
430032313320130023
5203344403311021
610011152243335
7643324554461
oct141667703413
936810667455
1013134432011
115630054198
12266684054b
1313141ac87c
148c8560831
1551d15885b
hex30edf870b

13134432011 has 4 divisors (see below), whose sum is σ = 13137163512. Its totient is φ = 13131700512.

The previous prime is 13134431987. The next prime is 13134432019. The reversal of 13134432011 is 11023443131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11023443131 = 107103022833.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13134432011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13134432019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1358525 + ... + 1368158.

It is an arithmetic number, because the mean of its divisors is an integer number (3284290878).

Almost surely, 213134432011 is an apocalyptic number.

13134432011 is a deficient number, since it is larger than the sum of its proper divisors (2731501).

13134432011 is an equidigital number, since it uses as much as digits as its factorization.

13134432011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2731500.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13134432011 its reverse (11023443131), we get a palindrome (24157875142).

The spelling of 13134432011 in words is "thirteen billion, one hundred thirty-four million, four hundred thirty-two thousand, eleven".

Divisors: 1 4817 2726683 13134432011