Base | Representation |
---|---|
bin | 11101110111010011111011… |
… | …111001011001101111100111 |
3 | 122020001101122220121220111120 |
4 | 131313103323321121233213 |
5 | 114203421134431244201 |
6 | 1143202430030305023 |
7 | 36444212561415111 |
oct | 3567237371315747 |
9 | 566041586556446 |
10 | 131344326040551 |
11 | 389398a7a01788 |
12 | 128934b1058173 |
13 | 5839941a6b090 |
14 | 246115669a3b1 |
15 | 102b879b80536 |
hex | 7774fbe59be7 |
131344326040551 has 16 divisors (see below), whose sum is σ = 188776426312320. Its totient is φ = 80750372421600.
The previous prime is 131344326040547. The next prime is 131344326040553. The reversal of 131344326040551 is 155040623443131.
It is not a de Polignac number, because 131344326040551 - 22 = 131344326040547 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131344326040553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1602148941 + ... + 1602230918.
It is an arithmetic number, because the mean of its divisors is an integer number (11798526644520).
Almost surely, 2131344326040551 is an apocalyptic number.
131344326040551 is a deficient number, since it is larger than the sum of its proper divisors (57432100271769).
131344326040551 is a wasteful number, since it uses less digits than its factorization.
131344326040551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3204380926.
The product of its (nonzero) digits is 518400, while the sum is 42.
Adding to 131344326040551 its reverse (155040623443131), we get a palindrome (286384949483682).
The spelling of 131344326040551 in words is "one hundred thirty-one trillion, three hundred forty-four billion, three hundred twenty-six million, forty thousand, five hundred fifty-one".
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