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1313443430412 = 223109453619201
BaseRepresentation
bin10011000111001111010…
…101000100000000001100
311122120020010112110212020
4103013033111010000030
5133004413004233122
62443215415010140
7163615231644141
oct23071725040014
94576203473766
101313443430412
11467034636463
12192679669950
1396b1b3057a9
14477dcb823c8
1524274268c5c
hex131cf54400c

1313443430412 has 12 divisors (see below), whose sum is σ = 3064701337656. Its totient is φ = 437814476800.

The previous prime is 1313443430399. The next prime is 1313443430423. The reversal of 1313443430412 is 2140343443131.

It is a tau number, because it is divible by the number of its divisors (12).

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54726809589 + ... + 54726809612.

It is an arithmetic number, because the mean of its divisors is an integer number (255391778138).

Almost surely, 21313443430412 is an apocalyptic number.

1313443430412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1313443430412 is an abundant number, since it is smaller than the sum of its proper divisors (1751257907244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313443430412 is a wasteful number, since it uses less digits than its factorization.

1313443430412 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109453619208 (or 109453619206 counting only the distinct ones).

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1313443430412 its reverse (2140343443131), we get a palindrome (3453786873543).

The spelling of 1313443430412 in words is "one trillion, three hundred thirteen billion, four hundred forty-three million, four hundred thirty thousand, four hundred twelve".

Divisors: 1 2 3 4 6 12 109453619201 218907238402 328360857603 437814476804 656721715206 1313443430412