Base | Representation |
---|---|
bin | 11101110111010011111101… |
… | …100001100001100010010101 |
3 | 122020001101201210222122001120 |
4 | 131313103331201201202111 |
5 | 114203421213423213240 |
6 | 1143202432443314153 |
7 | 36444213342416055 |
oct | 3567237541414225 |
9 | 566041653878046 |
10 | 131344353335445 |
11 | 38939911354848 |
12 | 128934ba21b959 |
13 | 58399476069c3 |
14 | 246115a163565 |
15 | 102b87c272ad0 |
hex | 7774fd861895 |
131344353335445 has 16 divisors (see below), whose sum is σ = 210151282368192. Its totient is φ = 70050216101760.
The previous prime is 131344353335417. The next prime is 131344353335467. The reversal of 131344353335445 is 544533353443131.
It is not a de Polignac number, because 131344353335445 - 29 = 131344353334933 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4244574 + ... + 16754256.
It is an arithmetic number, because the mean of its divisors is an integer number (13134455148012).
Almost surely, 2131344353335445 is an apocalyptic number.
131344353335445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131344353335445 is a deficient number, since it is larger than the sum of its proper divisors (78806929032747).
131344353335445 is a wasteful number, since it uses less digits than its factorization.
131344353335445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13209652.
The product of its digits is 23328000, while the sum is 51.
The spelling of 131344353335445 in words is "one hundred thirty-one trillion, three hundred forty-four billion, three hundred fifty-three million, three hundred thirty-five thousand, four hundred forty-five".
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