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131344402255223 = 714111839274093
BaseRepresentation
bin11101110111010100000000…
…011100001000110101110111
3122020001101212020001000101012
4131313110000130020311313
5114203421313434131343
61143202441352022435
736444214505264243
oct3567240034106567
9566041766030335
10131344402255223
1138939936a27a13
1212893512691a1b
1358399547a4511
142461162859423
15102b8816d7718
hex777500708d77

131344402255223 has 4 divisors (see below), whose sum is σ = 131346241600728. Its totient is φ = 131342562909720.

The previous prime is 131344402255181. The next prime is 131344402255279. The reversal of 131344402255223 is 322552204443131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131344402255223 - 216 = 131344402189687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131344402252223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 919565636 + ... + 919708457.

It is an arithmetic number, because the mean of its divisors is an integer number (32836560400182).

Almost surely, 2131344402255223 is an apocalyptic number.

131344402255223 is a deficient number, since it is larger than the sum of its proper divisors (1839345505).

131344402255223 is an equidigital number, since it uses as much as digits as its factorization.

131344402255223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1839345504.

The product of its (nonzero) digits is 691200, while the sum is 41.

Adding to 131344402255223 its reverse (322552204443131), we get a palindrome (453896606698354).

The spelling of 131344402255223 in words is "one hundred thirty-one trillion, three hundred forty-four billion, four hundred two million, two hundred fifty-five thousand, two hundred twenty-three".

Divisors: 1 71411 1839274093 131344402255223