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131344424514139 is a prime number
BaseRepresentation
bin11101110111010100000001…
…110001000011001001011011
3122020001101220202220212212111
4131313110001301003021123
5114203421340133423024
61143202443505053151
736444215165422114
oct3567240161031133
9566041822825774
10131344424514139
1138939948550411
121289351a0271b7
135839959298b85
1424611657b120b
15102b883632a94
hex777501c4325b

131344424514139 has 2 divisors, whose sum is σ = 131344424514140. Its totient is φ = 131344424514138.

The previous prime is 131344424514119. The next prime is 131344424514221. The reversal of 131344424514139 is 931415424443131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131344424514139 - 213 = 131344424505947 is a prime.

It is a super-2 number, since 2×1313444245141392 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131344424514092 and 131344424514101.

It is not a weakly prime, because it can be changed into another prime (131344424514119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672212257069 + 65672212257070.

It is an arithmetic number, because the mean of its divisors is an integer number (65672212257070).

Almost surely, 2131344424514139 is an apocalyptic number.

131344424514139 is a deficient number, since it is larger than the sum of its proper divisors (1).

131344424514139 is an equidigital number, since it uses as much as digits as its factorization.

131344424514139 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2488320, while the sum is 49.

The spelling of 131344424514139 in words is "one hundred thirty-one trillion, three hundred forty-four billion, four hundred twenty-four million, five hundred fourteen thousand, one hundred thirty-nine".