Base | Representation |
---|---|
bin | 11101110111010100000110… |
… | …010001011001111101110111 |
3 | 122020001102010001011022010221 |
4 | 131313110012101121331313 |
5 | 114203422014011330304 |
6 | 1143202455205155211 |
7 | 36444220104062632 |
oct | 3567240621317567 |
9 | 566042101138127 |
10 | 131344500105079 |
11 | 3893998718aa68 |
12 | 1289353b3bbb07 |
13 | 583996bb44441 |
14 | 246117184ac19 |
15 | 102b88a0b5054 |
hex | 777506459f77 |
131344500105079 has 2 divisors, whose sum is σ = 131344500105080. Its totient is φ = 131344500105078.
The previous prime is 131344500105031. The next prime is 131344500105103. The reversal of 131344500105079 is 970501005443131.
It is a strong prime.
It is an emirp because it is prime and its reverse (970501005443131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131344500105079 - 217 = 131344499974007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131344500109079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65672250052539 + 65672250052540.
It is an arithmetic number, because the mean of its divisors is an integer number (65672250052540).
Almost surely, 2131344500105079 is an apocalyptic number.
131344500105079 is a deficient number, since it is larger than the sum of its proper divisors (1).
131344500105079 is an equidigital number, since it uses as much as digits as its factorization.
131344500105079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 226800, while the sum is 43.
The spelling of 131344500105079 in words is "one hundred thirty-one trillion, three hundred forty-four billion, five hundred million, one hundred five thousand, seventy-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •