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131345425402393 = 699311878214603
BaseRepresentation
bin11101110111010100111101…
…011011001000101000011001
3122020001111111112021021102211
4131313110331123020220121
5114203430412400334033
61143203131101355121
736444252041012506
oct3567247533105031
9566044445237384
10131345425402393
113893a311520594
1212893759268aa1
135839a88757447
14246121c6b04ad
15102b8e143c2cd
hex77753d6c8a19

131345425402393 has 4 divisors (see below), whose sum is σ = 131347303686928. Its totient is φ = 131343547117860.

The previous prime is 131345425402319. The next prime is 131345425402441. The reversal of 131345425402393 is 393204524543131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131345425402393 - 213 = 131345425394201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131345425402193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 939037371 + ... + 939177232.

It is an arithmetic number, because the mean of its divisors is an integer number (32836825921732).

Almost surely, 2131345425402393 is an apocalyptic number.

It is an amenable number.

131345425402393 is a deficient number, since it is larger than the sum of its proper divisors (1878284535).

131345425402393 is an equidigital number, since it uses as much as digits as its factorization.

131345425402393 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1878284534.

The product of its (nonzero) digits is 4665600, while the sum is 49.

The spelling of 131345425402393 in words is "one hundred thirty-one trillion, three hundred forty-five billion, four hundred twenty-five million, four hundred two thousand, three hundred ninety-three".

Divisors: 1 69931 1878214603 131345425402393