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1313454554051 = 6831923066697
BaseRepresentation
bin10011000111001111111…
…111011111101111000011
311122120020220110121121212
4103013033333133233003
5133004423331212201
62443220453240335
7163615425333443
oct23071777375703
94576226417555
101313454554051
1146703a943852
121926813330ab
1396b206cb923
144780043a123
1524275214abb
hex131cffdfbc3

1313454554051 has 4 divisors (see below), whose sum is σ = 1315377621432. Its totient is φ = 1311531486672.

The previous prime is 1313454553981. The next prime is 1313454554141. The reversal of 1313454554051 is 1504554543131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313454554051 - 230 = 1312380812227 is a prime.

It is a super-2 number, since 2×13134545540512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313454554851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 961532666 + ... + 961534031.

It is an arithmetic number, because the mean of its divisors is an integer number (328844405358).

Almost surely, 21313454554051 is an apocalyptic number.

1313454554051 is a deficient number, since it is larger than the sum of its proper divisors (1923067381).

1313454554051 is an equidigital number, since it uses as much as digits as its factorization.

1313454554051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1923067380.

The product of its (nonzero) digits is 360000, while the sum is 41.

The spelling of 1313454554051 in words is "one trillion, three hundred thirteen billion, four hundred fifty-four million, five hundred fifty-four thousand, fifty-one".

Divisors: 1 683 1923066697 1313454554051