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1313454554141 is a prime number
BaseRepresentation
bin10011000111001111111…
…111011111110000011101
311122120020220110121202012
4103013033333133300131
5133004423331213031
62443220453241005
7163615425333632
oct23071777376035
94576226417665
101313454554141
1146703a943924
12192681333165
1396b206cb992
144780043a189
1524275214b2b
hex131cffdfc1d

1313454554141 has 2 divisors, whose sum is σ = 1313454554142. Its totient is φ = 1313454554140.

The previous prime is 1313454553981. The next prime is 1313454554221. The reversal of 1313454554141 is 1414554543131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1313421434116 + 33120025 = 1146046^2 + 5755^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313454554141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313454554941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656727277070 + 656727277071.

It is an arithmetic number, because the mean of its divisors is an integer number (656727277071).

Almost surely, 21313454554141 is an apocalyptic number.

It is an amenable number.

1313454554141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313454554141 is an equidigital number, since it uses as much as digits as its factorization.

1313454554141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 288000, while the sum is 41.

It can be divided in two parts, 1313 and 454554141, that added together give a palindrome (454555454).

The spelling of 1313454554141 in words is "one trillion, three hundred thirteen billion, four hundred fifty-four million, five hundred fifty-four thousand, one hundred forty-one".