Base | Representation |
---|---|
bin | 11000011101110010… |
… | …11111101111101011 |
3 | 1020220101112202221120 |
4 | 30032321133233223 |
5 | 203400010331042 |
6 | 10011205310323 |
7 | 643331266221 |
oct | 141671375753 |
9 | 36811482846 |
10 | 13134855147 |
11 | 5630313097 |
12 | 2666a053a3 |
13 | 13142ca34b |
14 | 8c8630b11 |
15 | 51d1dddec |
hex | 30ee5fbeb |
13134855147 has 4 divisors (see below), whose sum is σ = 17513140200. Its totient is φ = 8756570096.
The previous prime is 13134855143. The next prime is 13134855191. The reversal of 13134855147 is 74155843131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13134855147 - 22 = 13134855143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13134855099 and 13134855108.
It is not an unprimeable number, because it can be changed into a prime (13134855143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2189142522 + ... + 2189142527.
It is an arithmetic number, because the mean of its divisors is an integer number (4378285050).
Almost surely, 213134855147 is an apocalyptic number.
13134855147 is a deficient number, since it is larger than the sum of its proper divisors (4378285053).
13134855147 is an equidigital number, since it uses as much as digits as its factorization.
13134855147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4378285052.
The product of its digits is 201600, while the sum is 42.
The spelling of 13134855147 in words is "thirteen billion, one hundred thirty-four million, eight hundred fifty-five thousand, one hundred forty-seven".
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