Base | Representation |
---|---|
bin | 11101110111011001100010… |
… | …011111010110001000011011 |
3 | 122020001222012012011000200120 |
4 | 131313121202133112020123 |
5 | 114204021000102334210 |
6 | 1143205303022204323 |
7 | 36444514633243500 |
oct | 3567314237261033 |
9 | 566058165130616 |
10 | 131350342230555 |
11 | 38941404990338 |
12 | 128946aba236a3 |
13 | 583a3902b5016 |
14 | 24615676c14a7 |
15 | 102bacce15270 |
hex | 7776627d621b |
131350342230555 has 48 divisors (see below), whose sum is σ = 249674015761920. Its totient is φ = 58768299000768.
The previous prime is 131350342230533. The next prime is 131350342230623. The reversal of 131350342230555 is 555032243053131.
It is not a de Polignac number, because 131350342230555 - 215 = 131350342197787 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1901113845 + ... + 1901182934.
It is an arithmetic number, because the mean of its divisors is an integer number (5201541995040).
Almost surely, 2131350342230555 is an apocalyptic number.
131350342230555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131350342230555 is a deficient number, since it is larger than the sum of its proper divisors (118323673531365).
131350342230555 is a wasteful number, since it uses less digits than its factorization.
131350342230555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3802296848 (or 3802296841 counting only the distinct ones).
The product of its (nonzero) digits is 810000, while the sum is 42.
Adding to 131350342230555 its reverse (555032243053131), we get a palindrome (686382585283686).
The spelling of 131350342230555 in words is "one hundred thirty-one trillion, three hundred fifty billion, three hundred forty-two million, two hundred thirty thousand, five hundred fifty-five".
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