Base | Representation |
---|---|
bin | 11101110111011001101011… |
… | …111110101010001010010001 |
3 | 122020001222121021201101202111 |
4 | 131313121223332222022101 |
5 | 114204021311331342001 |
6 | 1143205330510345321 |
7 | 36444521605404463 |
oct | 3567315376521221 |
9 | 566058537641674 |
10 | 131350501434001 |
11 | 38941486839233 |
12 | 128947351bb241 |
13 | 583a3b7287045 |
14 | 24615808c4133 |
15 | 102badbdb1851 |
hex | 77766bfaa291 |
131350501434001 has 8 divisors (see below), whose sum is σ = 139220232227424. Its totient is φ = 123496685163840.
The previous prime is 131350501433971. The next prime is 131350501434017. The reversal of 131350501434001 is 100434105053131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131350501434001 - 243 = 122554408411793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131350501434041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3978613815 + ... + 3978646828.
It is an arithmetic number, because the mean of its divisors is an integer number (17402529028428).
Almost surely, 2131350501434001 is an apocalyptic number.
It is an amenable number.
131350501434001 is a deficient number, since it is larger than the sum of its proper divisors (7869730793423).
131350501434001 is an equidigital number, since it uses as much as digits as its factorization.
131350501434001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7957261631.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 131350501434001 its reverse (100434105053131), we get a palindrome (231784606487132).
The spelling of 131350501434001 in words is "one hundred thirty-one trillion, three hundred fifty billion, five hundred one million, four hundred thirty-four thousand, one".
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