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131351115613 is a prime number
BaseRepresentation
bin111101001010100100…
…0101111011101011101
3110120001002022000210211
41322111020233131131
54123001341144423
6140201502132421
712330001026634
oct1722510573535
9416032260724
10131351115613
115078430a303
1221559281111
13c503a98923
146500ad451b
15363b79e10d
hex1e9522f75d

131351115613 has 2 divisors, whose sum is σ = 131351115614. Its totient is φ = 131351115612.

The previous prime is 131351115607. The next prime is 131351115659. The reversal of 131351115613 is 316511153131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103222123524 + 28128992089 = 321282^2 + 167717^2 .

It is an emirp because it is prime and its reverse (316511153131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131351115613 - 29 = 131351115101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131351115673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65675557806 + 65675557807.

It is an arithmetic number, because the mean of its divisors is an integer number (65675557807).

Almost surely, 2131351115613 is an apocalyptic number.

It is an amenable number.

131351115613 is a deficient number, since it is larger than the sum of its proper divisors (1).

131351115613 is an equidigital number, since it uses as much as digits as its factorization.

131351115613 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4050, while the sum is 31.

Adding to 131351115613 its reverse (316511153131), we get a palindrome (447862268744).

The spelling of 131351115613 in words is "one hundred thirty-one billion, three hundred fifty-one million, one hundred fifteen thousand, six hundred thirteen".