Base | Representation |
---|---|
bin | 111101001010100100… |
… | …0101111011101011101 |
3 | 110120001002022000210211 |
4 | 1322111020233131131 |
5 | 4123001341144423 |
6 | 140201502132421 |
7 | 12330001026634 |
oct | 1722510573535 |
9 | 416032260724 |
10 | 131351115613 |
11 | 5078430a303 |
12 | 21559281111 |
13 | c503a98923 |
14 | 6500ad451b |
15 | 363b79e10d |
hex | 1e9522f75d |
131351115613 has 2 divisors, whose sum is σ = 131351115614. Its totient is φ = 131351115612.
The previous prime is 131351115607. The next prime is 131351115659. The reversal of 131351115613 is 316511153131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103222123524 + 28128992089 = 321282^2 + 167717^2 .
It is an emirp because it is prime and its reverse (316511153131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131351115613 - 29 = 131351115101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131351115673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65675557806 + 65675557807.
It is an arithmetic number, because the mean of its divisors is an integer number (65675557807).
Almost surely, 2131351115613 is an apocalyptic number.
It is an amenable number.
131351115613 is a deficient number, since it is larger than the sum of its proper divisors (1).
131351115613 is an equidigital number, since it uses as much as digits as its factorization.
131351115613 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4050, while the sum is 31.
Adding to 131351115613 its reverse (316511153131), we get a palindrome (447862268744).
The spelling of 131351115613 in words is "one hundred thirty-one billion, three hundred fifty-one million, one hundred fifteen thousand, six hundred thirteen".
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