Base | Representation |
---|---|
bin | 111101001010100100… |
… | …0110100000001111011 |
3 | 110120001002022222111002 |
4 | 1322111020310001323 |
5 | 4123001342244311 |
6 | 140201502355215 |
7 | 12330001135334 |
oct | 1722510640173 |
9 | 416032288432 |
10 | 131351134331 |
11 | 5078432237a |
12 | 2155928bb0b |
13 | c503aa42c1 |
14 | 6500adb28b |
15 | 363b7a493b |
hex | 1e9523407b |
131351134331 has 2 divisors, whose sum is σ = 131351134332. Its totient is φ = 131351134330.
The previous prime is 131351134307. The next prime is 131351134357. The reversal of 131351134331 is 133431153131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131351134331 is a prime.
It is a super-2 number, since 2×1313511343312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131351134294 and 131351134303.
It is not a weakly prime, because it can be changed into another prime (131351134361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65675567165 + 65675567166.
It is an arithmetic number, because the mean of its divisors is an integer number (65675567166).
Almost surely, 2131351134331 is an apocalyptic number.
131351134331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131351134331 is an equidigital number, since it uses as much as digits as its factorization.
131351134331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4860, while the sum is 29.
Adding to 131351134331 its reverse (133431153131), we get a palindrome (264782287462).
The spelling of 131351134331 in words is "one hundred thirty-one billion, three hundred fifty-one million, one hundred thirty-four thousand, three hundred thirty-one".
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