Base | Representation |
---|---|
bin | 11101110111011010011100… |
… | …111010000111000110100011 |
3 | 122020002001201111101000002001 |
4 | 131313122130322013012203 |
5 | 114204030002003403121 |
6 | 1143205544153104431 |
7 | 36444551134022056 |
oct | 3567323472070643 |
9 | 566061644330061 |
10 | 131351322325411 |
11 | 38941868149091 |
12 | 128949240b8117 |
13 | 583a4b8372cc6 |
14 | 246161b92aa9d |
15 | 102bb38eb3991 |
hex | 77769ce871a3 |
131351322325411 has 4 divisors (see below), whose sum is σ = 139077870697512. Its totient is φ = 123624773953312.
The previous prime is 131351322325357. The next prime is 131351322325463. The reversal of 131351322325411 is 114523223153131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131351322325411 - 211 = 131351322323363 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131351322323411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3863274186025 + ... + 3863274186058.
It is an arithmetic number, because the mean of its divisors is an integer number (34769467674378).
Almost surely, 2131351322325411 is an apocalyptic number.
131351322325411 is a deficient number, since it is larger than the sum of its proper divisors (7726548372101).
131351322325411 is an equidigital number, since it uses as much as digits as its factorization.
131351322325411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7726548372100.
The product of its digits is 64800, while the sum is 37.
Adding to 131351322325411 its reverse (114523223153131), we get a palindrome (245874545478542).
The spelling of 131351322325411 in words is "one hundred thirty-one trillion, three hundred fifty-one billion, three hundred twenty-two million, three hundred twenty-five thousand, four hundred eleven".
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