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131352017 is a prime number
BaseRepresentation
bin1111101010001…
…00010111010001
3100011011101002112
413311010113101
5232111231032
621011155105
73153321326
oct765042721
9304141075
10131352017
1168165795
1237ba5a95
132129ccb4
1413632b4d
15b7e91b2
hex7d445d1

131352017 has 2 divisors, whose sum is σ = 131352018. Its totient is φ = 131352016.

The previous prime is 131351977. The next prime is 131352029. The reversal of 131352017 is 710253131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126135361 + 5216656 = 11231^2 + 2284^2 .

It is a cyclic number.

It is not a de Polignac number, because 131352017 - 212 = 131347921 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131351983 and 131352001.

It is not a weakly prime, because it can be changed into another prime (131352097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65676008 + 65676009.

It is an arithmetic number, because the mean of its divisors is an integer number (65676009).

Almost surely, 2131352017 is an apocalyptic number.

It is an amenable number.

131352017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131352017 is an equidigital number, since it uses as much as digits as its factorization.

131352017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 23.

The square root of 131352017 is about 11460.8907594480. The cubic root of 131352017 is about 508.3298137772.

The spelling of 131352017 in words is "one hundred thirty-one million, three hundred fifty-two thousand, seventeen".