Base | Representation |
---|---|
bin | 111101001010100110… |
… | …0101010001011001111 |
3 | 110120001011020012111021 |
4 | 1322111030222023033 |
5 | 4123002122030133 |
6 | 140201540135011 |
7 | 12330012534616 |
oct | 1722514521317 |
9 | 416034205437 |
10 | 131352142543 |
11 | 50784950906 |
12 | 21559697467 |
13 | c50406818b |
14 | 6500cc087d |
15 | 363b90352d |
hex | 1e9532a2cf |
131352142543 has 2 divisors, whose sum is σ = 131352142544. Its totient is φ = 131352142542.
The previous prime is 131352142529. The next prime is 131352142547. The reversal of 131352142543 is 345241253131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131352142543 - 25 = 131352142511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131352142499 and 131352142508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131352142547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65676071271 + 65676071272.
It is an arithmetic number, because the mean of its divisors is an integer number (65676071272).
Almost surely, 2131352142543 is an apocalyptic number.
131352142543 is a deficient number, since it is larger than the sum of its proper divisors (1).
131352142543 is an equidigital number, since it uses as much as digits as its factorization.
131352142543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 43200, while the sum is 34.
Adding to 131352142543 its reverse (345241253131), we get a palindrome (476593395674).
The spelling of 131352142543 in words is "one hundred thirty-one billion, three hundred fifty-two million, one hundred forty-two thousand, five hundred forty-three".
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