Base | Representation |
---|---|
bin | 11101110111011100011110… |
… | …111000111101001001000000 |
3 | 122020002021100110210211021221 |
4 | 131313130132320331021000 |
5 | 114204043433240414134 |
6 | 1143210544413524424 |
7 | 36444656153663332 |
oct | 3567343670751100 |
9 | 566067313724257 |
10 | 131353503060544 |
11 | 3894278710a726 |
12 | 128952324a3714 |
13 | 583a7750baa1b |
14 | 24617873d1452 |
15 | 102bc156775b4 |
hex | 77771ee3d240 |
131353503060544 has 28 divisors (see below), whose sum is σ = 267699326765884. Its totient is φ = 63901704190464.
The previous prime is 131353503060503. The next prime is 131353503060553. The reversal of 131353503060544 is 445060305353131.
131353503060544 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 64084635962944 + 67268867097600 = 8005288^2 + 8201760^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 131353503060544.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27735112299 + ... + 27735117034.
Almost surely, 2131353503060544 is an apocalyptic number.
It is an amenable number.
131353503060544 is an abundant number, since it is smaller than the sum of its proper divisors (136345823705340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131353503060544 is an equidigital number, since it uses as much as digits as its factorization.
131353503060544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55470229382 (or 55470229372 counting only the distinct ones).
The product of its (nonzero) digits is 972000, while the sum is 43.
The spelling of 131353503060544 in words is "one hundred thirty-one trillion, three hundred fifty-three billion, five hundred three million, sixty thousand, five hundred forty-four".
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