13135403 has 4 divisors (see below), whose sum is σ = 13826760. Its totient is φ = 12444048.

The previous prime is 13135399. The next prime is 13135433. The reversal of 13135403 is 30453131.

It is a happy number.

13135403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30453131 = 547 ⋅55673.

It is a cyclic number.

It is not a de Polignac number, because 13135403 - 2² = 13135399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13135433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345650 + ... + 345687.

It is an arithmetic number, because the mean of its divisors is an integer number (3456690).

Almost surely, 2^13135403 is an apocalyptic number.

13135403 is a deficient number, since it is larger than the sum of its proper divisors (691357).

13135403 is an equidigital number, since it uses as much as digits as its factorization.

13135403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 691356.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 13135403 is about 3624.2796525655. The cubic root of 13135403 is about 235.9470040439.

Adding to 13135403 its reverse (30453131), we get a palindrome (43588534).

The spelling of 13135403 in words is "thirteen million, one hundred thirty-five thousand, four hundred three".