Base | Representation |
---|---|
bin | 10011000111010101110… |
… | …011101001011011001001 |
3 | 11122120111201001001000111 |
4 | 103013111303221123021 |
5 | 133010123320030210 |
6 | 2443234300234321 |
7 | 163621021503100 |
oct | 23072563513311 |
9 | 4576451031014 |
10 | 1313552111305 |
11 | 46708aa16a85 |
12 | 1926a9b3b9a1 |
13 | 96b37998605 |
14 | 4780d393037 |
15 | 2427da8588a |
hex | 131d5ce96c9 |
1313552111305 has 24 divisors (see below), whose sum is σ = 1833664277952. Its totient is φ = 900695531232.
The previous prime is 1313552111279. The next prime is 1313552111351. The reversal of 1313552111305 is 5031112553131.
It is not a de Polignac number, because 1313552111305 - 27 = 1313552111177 is a prime.
It is a super-2 number, since 2×13135521113052 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12905644 + ... + 13007026.
It is an arithmetic number, because the mean of its divisors is an integer number (76402678248).
Almost surely, 21313552111305 is an apocalyptic number.
It is an amenable number.
1313552111305 is a deficient number, since it is larger than the sum of its proper divisors (520112166647).
1313552111305 is a wasteful number, since it uses less digits than its factorization.
1313552111305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154285 (or 154278 counting only the distinct ones).
The product of its (nonzero) digits is 6750, while the sum is 31.
Adding to 1313552111305 its reverse (5031112553131), we get a palindrome (6344664664436).
The spelling of 1313552111305 in words is "one trillion, three hundred thirteen billion, five hundred fifty-two million, one hundred eleven thousand, three hundred five".
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