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1313552111305 = 57252883101383
BaseRepresentation
bin10011000111010101110…
…011101001011011001001
311122120111201001001000111
4103013111303221123021
5133010123320030210
62443234300234321
7163621021503100
oct23072563513311
94576451031014
101313552111305
1146708aa16a85
121926a9b3b9a1
1396b37998605
144780d393037
152427da8588a
hex131d5ce96c9

1313552111305 has 24 divisors (see below), whose sum is σ = 1833664277952. Its totient is φ = 900695531232.

The previous prime is 1313552111279. The next prime is 1313552111351. The reversal of 1313552111305 is 5031112553131.

It is not a de Polignac number, because 1313552111305 - 27 = 1313552111177 is a prime.

It is a super-2 number, since 2×13135521113052 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12905644 + ... + 13007026.

It is an arithmetic number, because the mean of its divisors is an integer number (76402678248).

Almost surely, 21313552111305 is an apocalyptic number.

It is an amenable number.

1313552111305 is a deficient number, since it is larger than the sum of its proper divisors (520112166647).

1313552111305 is a wasteful number, since it uses less digits than its factorization.

1313552111305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154285 (or 154278 counting only the distinct ones).

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 1313552111305 its reverse (5031112553131), we get a palindrome (6344664664436).

The spelling of 1313552111305 in words is "one trillion, three hundred thirteen billion, five hundred fifty-two million, one hundred eleven thousand, three hundred five".

Divisors: 1 5 7 35 49 245 52883 101383 264415 370181 506915 709681 1850905 2591267 3548405 4967767 12956335 24838835 5361437189 26807185945 37530060323 187650301615 262710422261 1313552111305