1313557051435 has 4 divisors (see below), whose sum is σ = 1576268461728. Its totient is φ = 1050845641144.

The previous prime is 1313557051423. The next prime is 1313557051493. The reversal of 1313557051435 is 5341507553131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313557051435 is a prime.

It is a super-2 number, since 2×1313557051435² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313557051391 and 1313557051400.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131355705139 + ... + 131355705148.

It is an arithmetic number, because the mean of its divisors is an integer number (394067115432).

Almost surely, 2^{1313557051435} is an apocalyptic number.

1313557051435 is a deficient number, since it is larger than the sum of its proper divisors (262711410293).

1313557051435 is an equidigital number, since it uses as much as digits as its factorization.

1313557051435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262711410292.

The product of its (nonzero) digits is 472500, while the sum is 43.

The spelling of 1313557051435 in words is "one trillion, three hundred thirteen billion, five hundred fifty-seven million, fifty-one thousand, four hundred thirty-five".