1313563524343 has 4 divisors (see below), whose sum is σ = 1501215456400. Its totient is φ = 1125911592288.

The previous prime is 1313563524337. The next prime is 1313563524359. The reversal of 1313563524343 is 3434253653131.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-1313563524343 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1313563524343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313563524743) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93825966018 + ... + 93825966031.

It is an arithmetic number, because the mean of its divisors is an integer number (375303864100).

Almost surely, 2^{1313563524343} is an apocalyptic number.

1313563524343 is a deficient number, since it is larger than the sum of its proper divisors (187651932057).

1313563524343 is an equidigital number, since it uses as much as digits as its factorization.

1313563524343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187651932056.

The product of its digits is 1166400, while the sum is 43.

The spelling of 1313563524343 in words is "one trillion, three hundred thirteen billion, five hundred sixty-three million, five hundred twenty-four thousand, three hundred forty-three".