Base | Representation |
---|---|
bin | 10011000111010110100… |
… | …010110000010000001001 |
3 | 11122120112120021102022002 |
4 | 103013112202300100021 |
5 | 133010140000210131 |
6 | 2443235421040345 |
7 | 163621231454201 |
oct | 23072642602011 |
9 | 4576476242262 |
10 | 1313564460041 |
11 | 467096990849 |
12 | 1926b20b60b5 |
13 | 96b3a400262 |
14 | 47810c89401 |
15 | 2427ebc46cb |
hex | 131d68b0409 |
1313564460041 has 2 divisors, whose sum is σ = 1313564460042. Its totient is φ = 1313564460040.
The previous prime is 1313564460011. The next prime is 1313564460071. The reversal of 1313564460041 is 1400644653131.
It is a balanced prime because it is at equal distance from previous prime (1313564460011) and next prime (1313564460071).
It can be written as a sum of positive squares in only one way, i.e., 870061738441 + 443502721600 = 932771^2 + 665960^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313564460041 - 222 = 1313560265737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313564459977 and 1313564460004.
It is not a weakly prime, because it can be changed into another prime (1313564460011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656782230020 + 656782230021.
It is an arithmetic number, because the mean of its divisors is an integer number (656782230021).
Almost surely, 21313564460041 is an apocalyptic number.
It is an amenable number.
1313564460041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313564460041 is an equidigital number, since it uses as much as digits as its factorization.
1313564460041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 38.
The spelling of 1313564460041 in words is "one trillion, three hundred thirteen billion, five hundred sixty-four million, four hundred sixty thousand, forty-one".
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