1313566253035 has 4 divisors (see below), whose sum is σ = 1576279503648. Its totient is φ = 1050853002424.

The previous prime is 1313566253029. The next prime is 1313566253093. The reversal of 1313566253035 is 5303526653131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313566253035 - 2¹³ = 1313566244843 is a prime.

It is a super-2 number, since 2×1313566253035² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313566252982 and 1313566253000.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131356625299 + ... + 131356625308.

It is an arithmetic number, because the mean of its divisors is an integer number (394069875912).

Almost surely, 2^{1313566253035} is an apocalyptic number.

1313566253035 is a deficient number, since it is larger than the sum of its proper divisors (262713250613).

1313566253035 is an equidigital number, since it uses as much as digits as its factorization.

1313566253035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262713250612.

The product of its (nonzero) digits is 729000, while the sum is 43.

The spelling of 1313566253035 in words is "one trillion, three hundred thirteen billion, five hundred sixty-six million, two hundred fifty-three thousand, thirty-five".