Search a number
-
+
131360036851 is a prime number
BaseRepresentation
bin111101001010110101…
…0110001011111110011
3110120001201002021110001
41322111222301133303
54123011132134401
6140202421250431
712330136614241
oct1722552613763
9416051067401
10131360036851
1150789352a2a
1221560263a17
13c5058a0474
146501d77791
15363c462601
hex1e95ab17f3

131360036851 has 2 divisors, whose sum is σ = 131360036852. Its totient is φ = 131360036850.

The previous prime is 131360036777. The next prime is 131360036891. The reversal of 131360036851 is 158630063131.

It is a strong prime.

It is an emirp because it is prime and its reverse (158630063131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131360036851 is a prime.

It is a super-3 number, since 3×1313600368513 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131360036851.

It is not a weakly prime, because it can be changed into another prime (131360036891) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65680018425 + 65680018426.

It is an arithmetic number, because the mean of its divisors is an integer number (65680018426).

Almost surely, 2131360036851 is an apocalyptic number.

131360036851 is a deficient number, since it is larger than the sum of its proper divisors (1).

131360036851 is an equidigital number, since it uses as much as digits as its factorization.

131360036851 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 37.

Adding to 131360036851 its reverse (158630063131), we get a palindrome (289990099982).

The spelling of 131360036851 in words is "one hundred thirty-one billion, three hundred sixty million, thirty-six thousand, eight hundred fifty-one".