Base | Representation |
---|---|
bin | 10011000111011000111… |
… | …101110111000010110111 |
3 | 11122120122101210011112021 |
4 | 103013120331313002313 |
5 | 133010230402321213 |
6 | 2443243432334011 |
7 | 163622234201656 |
oct | 23073075670267 |
9 | 4576571704467 |
10 | 1313605120183 |
11 | 467107932374 |
12 | 192703844307 |
13 | 96b45968405 |
14 | 4781643119d |
15 | 24283556d8d |
hex | 131d8f770b7 |
1313605120183 has 2 divisors, whose sum is σ = 1313605120184. Its totient is φ = 1313605120182.
The previous prime is 1313605120159. The next prime is 1313605120211. The reversal of 1313605120183 is 3810215063131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313605120183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313605120283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656802560091 + 656802560092.
It is an arithmetic number, because the mean of its divisors is an integer number (656802560092).
Almost surely, 21313605120183 is an apocalyptic number.
1313605120183 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313605120183 is an equidigital number, since it uses as much as digits as its factorization.
1313605120183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 1313605120183 in words is "one trillion, three hundred thirteen billion, six hundred five million, one hundred twenty thousand, one hundred eighty-three".
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