Base | Representation |
---|---|
bin | 11000011101111111… |
… | …10100000100000111 |
3 | 1020220111122220200022 |
4 | 30032333310010013 |
5 | 203400421324424 |
6 | 10011305005355 |
7 | 643351334405 |
oct | 141677640407 |
9 | 36814586608 |
10 | 13136511239 |
11 | 5631244365 |
12 | 266748385b |
13 | 131475a097 |
14 | 8c8942475 |
15 | 51d41995e |
hex | 30eff4107 |
13136511239 has 2 divisors, whose sum is σ = 13136511240. Its totient is φ = 13136511238.
The previous prime is 13136511229. The next prime is 13136511313. The reversal of 13136511239 is 93211563131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13136511239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13136511199 and 13136511208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13136511229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6568255619 + 6568255620.
It is an arithmetic number, because the mean of its divisors is an integer number (6568255620).
Almost surely, 213136511239 is an apocalyptic number.
13136511239 is a deficient number, since it is larger than the sum of its proper divisors (1).
13136511239 is an equidigital number, since it uses as much as digits as its factorization.
13136511239 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14580, while the sum is 35.
The spelling of 13136511239 in words is "thirteen billion, one hundred thirty-six million, five hundred eleven thousand, two hundred thirty-nine".
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