Base | Representation |
---|---|
bin | 10011000111011011110… |
… | …001010011011101010111 |
3 | 11122120202200022001111102 |
4 | 103013123301103131113 |
5 | 133010324423112333 |
6 | 2443252232500315 |
7 | 163623345061205 |
oct | 23073361233527 |
9 | 4576680261442 |
10 | 1313652160343 |
11 | 467131441336 |
12 | 19271754a69b |
13 | 96b52628523 |
14 | 4781c798075 |
15 | 24287749ae8 |
hex | 131dbc53757 |
1313652160343 has 2 divisors, whose sum is σ = 1313652160344. Its totient is φ = 1313652160342.
The previous prime is 1313652160213. The next prime is 1313652160427. The reversal of 1313652160343 is 3430612563131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313652160343 - 224 = 1313635383127 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313652160297 and 1313652160306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313652160043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656826080171 + 656826080172.
It is an arithmetic number, because the mean of its divisors is an integer number (656826080172).
Almost surely, 21313652160343 is an apocalyptic number.
1313652160343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313652160343 is an equidigital number, since it uses as much as digits as its factorization.
1313652160343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 38.
The spelling of 1313652160343 in words is "one trillion, three hundred thirteen billion, six hundred fifty-two million, one hundred sixty thousand, three hundred forty-three".
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