Base | Representation |
---|---|
bin | 111101001011000011… |
… | …0010000111000010001 |
3 | 110120002012122101210212 |
4 | 1322112012100320101 |
5 | 4123020003241111 |
6 | 140203235533505 |
7 | 12330255100241 |
oct | 1722606207021 |
9 | 416065571725 |
10 | 131367243281 |
11 | 5079242525a |
12 | 2156275a295 |
13 | c507224621 |
14 | 6502cd1b21 |
15 | 363cdd798b |
hex | 1e96190e11 |
131367243281 has 2 divisors, whose sum is σ = 131367243282. Its totient is φ = 131367243280.
The previous prime is 131367243247. The next prime is 131367243307. The reversal of 131367243281 is 182342763131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 81215880256 + 50151363025 = 284984^2 + 223945^2 .
It is a cyclic number.
It is not a de Polignac number, because 131367243281 - 214 = 131367226897 is a prime.
It is a super-2 number, since 2×1313672432812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131367243781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65683621640 + 65683621641.
It is an arithmetic number, because the mean of its divisors is an integer number (65683621641).
Almost surely, 2131367243281 is an apocalyptic number.
It is an amenable number.
131367243281 is a deficient number, since it is larger than the sum of its proper divisors (1).
131367243281 is an equidigital number, since it uses as much as digits as its factorization.
131367243281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 145152, while the sum is 41.
The spelling of 131367243281 in words is "one hundred thirty-one billion, three hundred sixty-seven million, two hundred forty-three thousand, two hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •