Base | Representation |
---|---|
bin | 10011000111101001011… |
… | …101101001010101111111 |
3 | 11122121100200120102202212 |
4 | 103013221131221111333 |
5 | 133011312230410002 |
6 | 2443331120411035 |
7 | 163632134531414 |
oct | 23075135512577 |
9 | 4577320512685 |
10 | 1313881888127 |
11 | 46723a089206 |
12 | 192780476a7b |
13 | 96b8b0c0923 |
14 | 478410b810b |
15 | 2429c9c7352 |
hex | 131e976957f |
1313881888127 has 2 divisors, whose sum is σ = 1313881888128. Its totient is φ = 1313881888126.
The previous prime is 1313881888097. The next prime is 1313881888159. The reversal of 1313881888127 is 7218881883131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313881888127 - 236 = 1245162411391 is a prime.
It is a super-4 number, since 4×13138818881274 (a number of 50 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313881888427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656940944063 + 656940944064.
It is an arithmetic number, because the mean of its divisors is an integer number (656940944064).
Almost surely, 21313881888127 is an apocalyptic number.
1313881888127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313881888127 is an equidigital number, since it uses as much as digits as its factorization.
1313881888127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4128768, while the sum is 59.
The spelling of 1313881888127 in words is "one trillion, three hundred thirteen billion, eight hundred eighty-one million, eight hundred eighty-eight thousand, one hundred twenty-seven".
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