Base | Representation |
---|---|
bin | 11000011110011000… |
… | …00101100001010111 |
3 | 1020220201201100220001 |
4 | 30033030011201113 |
5 | 203402232302341 |
6 | 10011501552131 |
7 | 643420564162 |
oct | 141714054127 |
9 | 36821640801 |
10 | 13139728471 |
11 | 5633041531 |
12 | 2668575647 |
13 | 131531557c |
14 | 8c913cad9 |
15 | 51d852d31 |
hex | 30f305857 |
13139728471 has 2 divisors, whose sum is σ = 13139728472. Its totient is φ = 13139728470.
The previous prime is 13139728457. The next prime is 13139728487. The reversal of 13139728471 is 17482793131.
It is a weak prime.
It is an emirp because it is prime and its reverse (17482793131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13139728471 - 25 = 13139728439 is a prime.
It is a super-3 number, since 3×131397284713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13139728411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6569864235 + 6569864236.
It is an arithmetic number, because the mean of its divisors is an integer number (6569864236).
Almost surely, 213139728471 is an apocalyptic number.
13139728471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13139728471 is an equidigital number, since it uses as much as digits as its factorization.
13139728471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 254016, while the sum is 46.
The spelling of 13139728471 in words is "thirteen billion, one hundred thirty-nine million, seven hundred twenty-eight thousand, four hundred seventy-one".
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