1314000320651 has 4 divisors (see below), whose sum is σ = 1316301547704. Its totient is φ = 1311699093600.

The previous prime is 1314000320603. The next prime is 1314000320747. The reversal of 1314000320651 is 1560230004131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314000320651 - 2²² = 1313996126347 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1314000320651.

It is not an unprimeable number, because it can be changed into a prime (1314000320851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1150612670 + ... + 1150613811.

It is an arithmetic number, because the mean of its divisors is an integer number (329075386926).

Almost surely, 2^{1314000320651} is an apocalyptic number.

1314000320651 is a deficient number, since it is larger than the sum of its proper divisors (2301227053).

1314000320651 is an equidigital number, since it uses as much as digits as its factorization.

1314000320651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2301227052.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 1314000320651 its reverse (1560230004131), we get a palindrome (2874230324782).

The spelling of 1314000320651 in words is "one trillion, three hundred fourteen billion, three hundred twenty thousand, six hundred fifty-one".