13140103411 has 2 divisors, whose sum is σ = 13140103412. Its totient is φ = 13140103410.

The previous prime is 13140103397. The next prime is 13140103451. The reversal of 13140103411 is 11430104131.

13140103411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (11430104131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13140103411 - 2¹³ = 13140095219 is a prime.

It is not a weakly prime, because it can be changed into another prime (13140103451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570051705 + 6570051706.

It is an arithmetic number, because the mean of its divisors is an integer number (6570051706).

Almost surely, 2^13140103411 is an apocalyptic number.

13140103411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140103411 is an equidigital number, since it uses as much as digits as its factorization.

13140103411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13140103411 its reverse (11430104131), we get a palindrome (24570207542).

The spelling of 13140103411 in words is "thirteen billion, one hundred forty million, one hundred three thousand, four hundred eleven".