131401114433 has 4 divisors (see below), whose sum is σ = 132702115668. Its totient is φ = 130100113200.

The previous prime is 131401114417. The next prime is 131401114463. The reversal of 131401114433 is 334411104131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 63913907344 + 67487207089 = 252812^2 + 259783^2 .

It is a cyclic number.

It is not a de Polignac number, because 131401114433 - 2⁴ = 131401114417 is a prime.

It is a super-2 number, since 2×131401114433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131401114463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650500466 + ... + 650500667.

It is an arithmetic number, because the mean of its divisors is an integer number (33175528917).

Almost surely, 2^131401114433 is an apocalyptic number.

It is an amenable number.

131401114433 is a deficient number, since it is larger than the sum of its proper divisors (1301001235).

131401114433 is a wasteful number, since it uses less digits than its factorization.

131401114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1301001234.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 131401114433 its reverse (334411104131), we get a palindrome (465812218564).

The spelling of 131401114433 in words is "one hundred thirty-one billion, four hundred one million, one hundred fourteen thousand, four hundred thirty-three".