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13140123030031 is a prime number
BaseRepresentation
bin1011111100110110110001…
…0111011001001000001111
31201112011221202200222111111
42333031230113121020033
53210241432443430111
643540253355232451
72524225332612004
oct277155427311017
951464852628444
1013140123030031
114206770985148
121582788748727
13744153b9553a
14335db1b1b8ab
1517bc110aba21
hexbf36c5d920f

13140123030031 has 2 divisors, whose sum is σ = 13140123030032. Its totient is φ = 13140123030030.

The previous prime is 13140123029977. The next prime is 13140123030037. The reversal of 13140123030031 is 13003032104131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13140123030031 - 215 = 13140122997263 is a prime.

It is a super-2 number, since 2×131401230300312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13140123029984 and 13140123030011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140123030037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570061515015 + 6570061515016.

It is an arithmetic number, because the mean of its divisors is an integer number (6570061515016).

Almost surely, 213140123030031 is an apocalyptic number.

13140123030031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140123030031 is an equidigital number, since it uses as much as digits as its factorization.

13140123030031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13140123030031 its reverse (13003032104131), we get a palindrome (26143155134162).

The spelling of 13140123030031 in words is "thirteen trillion, one hundred forty billion, one hundred twenty-three million, thirty thousand, thirty-one".