Base | Representation |
---|---|
bin | 11000011110011011… |
… | …01101011111101001 |
3 | 1020220202112000002011 |
4 | 30033031231133221 |
5 | 203402334414340 |
6 | 10011515035521 |
7 | 643424316613 |
oct | 141715553751 |
9 | 36822460064 |
10 | 13140154345 |
11 | 563330249a |
12 | 266873bba1 |
13 | 1315434376 |
14 | 8c920ddb3 |
15 | 51d8d90ea |
hex | 30f36d7e9 |
13140154345 has 4 divisors (see below), whose sum is σ = 15768185220. Its totient is φ = 10512123472.
The previous prime is 13140154319. The next prime is 13140154393. The reversal of 13140154345 is 54345104131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54345104131 = 191 ⋅284529341.
It can be written as a sum of positive squares in 2 ways, for example, as 3068827609 + 10071326736 = 55397^2 + 100356^2 .
It is a cyclic number.
It is not a de Polignac number, because 13140154345 - 219 = 13139630057 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1314015430 + ... + 1314015439.
It is an arithmetic number, because the mean of its divisors is an integer number (3942046305).
Almost surely, 213140154345 is an apocalyptic number.
It is an amenable number.
13140154345 is a deficient number, since it is larger than the sum of its proper divisors (2628030875).
13140154345 is an equidigital number, since it uses as much as digits as its factorization.
13140154345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2628030874.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13140154345 its reverse (54345104131), we get a palindrome (67485258476).
The spelling of 13140154345 in words is "thirteen billion, one hundred forty million, one hundred fifty-four thousand, three hundred forty-five".
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