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13140230079997 is a prime number
BaseRepresentation
bin1011111100110111001010…
…1111110000010111111101
31201112012020020010200110001
42333031302233300113331
53210242142400024442
643540312141514301
72524231102536016
oct277156257602775
951465206120401
1013140230079997
114206816351399
1215827b8572991
13744170106c07
14335dc202600d
1517bc1a6a52b7
hexbf372bf05fd

13140230079997 has 2 divisors, whose sum is σ = 13140230079998. Its totient is φ = 13140230079996.

The previous prime is 13140230079967. The next prime is 13140230080007. The reversal of 13140230079997 is 79997003204131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8079840360036 + 5060389719961 = 2842506^2 + 2249531^2 .

It is a cyclic number.

It is not a de Polignac number, because 13140230079997 - 231 = 13138082596349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13140230079937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6570115039998 + 6570115039999.

It is an arithmetic number, because the mean of its divisors is an integer number (6570115039999).

Almost surely, 213140230079997 is an apocalyptic number.

It is an amenable number.

13140230079997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13140230079997 is an equidigital number, since it uses as much as digits as its factorization.

13140230079997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2571912, while the sum is 55.

The spelling of 13140230079997 in words is "thirteen trillion, one hundred forty billion, two hundred thirty million, seventy-nine thousand, nine hundred ninety-seven".