131402304033041 has 4 divisors (see below), whose sum is σ = 131402353221300. Its totient is φ = 131402254844784.

The previous prime is 131402304033023. The next prime is 131402304033059. The reversal of 131402304033041 is 140330403204131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (131402304033023) and next prime (131402304033059).

It can be written as a sum of positive squares in 2 ways, for example, as 111228767715025 + 20173536318016 = 10546505^2 + 4491496^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131402304033041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131402304032995 and 131402304033013.

It is not an unprimeable number, because it can be changed into a prime (131402304033841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20341946 + ... + 26011523.

It is an arithmetic number, because the mean of its divisors is an integer number (32850588305325).

Almost surely, 2^{131402304033041} is an apocalyptic number.

It is an amenable number.

131402304033041 is a deficient number, since it is larger than the sum of its proper divisors (49188259).

131402304033041 is an equidigital number, since it uses as much as digits as its factorization.

131402304033041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49188258.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 131402304033041 its reverse (140330403204131), we get a palindrome (271732707237172).

The spelling of 131402304033041 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred four million, thirty-three thousand, forty-one".