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131402314102391 is a prime number
BaseRepresentation
bin11101111000001001111100…
…010000010011011001110111
3122020020221100012101122221122
4131320021330100103121313
5114210343414402234031
61143245220103534155
736451334560666643
oct3570117420233167
9566227305348848
10131402314102391
1138961454728932
12128a279515a35b
1358422537310c7
142463c97c67c23
15102d12096347b
hex77827c413677

131402314102391 has 2 divisors, whose sum is σ = 131402314102392. Its totient is φ = 131402314102390.

The previous prime is 131402314102333. The next prime is 131402314102481. The reversal of 131402314102391 is 193201413204131.

It is a weak prime.

It is an emirp because it is prime and its reverse (193201413204131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131402314102391 - 226 = 131402246993527 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131402314102691) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701157051195 + 65701157051196.

It is an arithmetic number, because the mean of its divisors is an integer number (65701157051196).

Almost surely, 2131402314102391 is an apocalyptic number.

131402314102391 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402314102391 is an equidigital number, since it uses as much as digits as its factorization.

131402314102391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 131402314102391 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred fourteen million, one hundred two thousand, three hundred ninety-one".