131402321110433 has 2 divisors, whose sum is σ = 131402321110434. Its totient is φ = 131402321110432.

The previous prime is 131402321110381. The next prime is 131402321110447. The reversal of 131402321110433 is 334011123204131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129204301375249 + 2198019735184 = 11366807^2 + 1482572^2 .

It is a cyclic number.

It is not a de Polignac number, because 131402321110433 - 2¹² = 131402321106337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131402321110396 and 131402321110405.

It is not a weakly prime, because it can be changed into another prime (131402321110453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65701160555216 + 65701160555217.

It is an arithmetic number, because the mean of its divisors is an integer number (65701160555217).

Almost surely, 2^{131402321110433} is an apocalyptic number.

It is an amenable number.

131402321110433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131402321110433 is an equidigital number, since it uses as much as digits as its factorization.

131402321110433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131402321110433 its reverse (334011123204131), we get a palindrome (465413444314564).

The spelling of 131402321110433 in words is "one hundred thirty-one trillion, four hundred two billion, three hundred twenty-one million, one hundred ten thousand, four hundred thirty-three".