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13140234420134 = 26570117210067
BaseRepresentation
bin1011111100110111001100…
…0000010011111110100110
31201112012020112022011222212
42333031303000103332212
53210242200002421014
643540312414523422
72524231154453333
oct277156300237646
951465215264885
1013140234420134
114206818846188
1215827b9b06572
13744170c96543
14335dc283598a
1517bc1ac6123e
hexbf373013fa6

13140234420134 has 4 divisors (see below), whose sum is σ = 19710351630204. Its totient is φ = 6570117210066.

The previous prime is 13140234420127. The next prime is 13140234420191. The reversal of 13140234420134 is 43102443204131.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13140234420134.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3285058605032 + ... + 3285058605035.

It is an arithmetic number, because the mean of its divisors is an integer number (4927587907551).

Almost surely, 213140234420134 is an apocalyptic number.

13140234420134 is a deficient number, since it is larger than the sum of its proper divisors (6570117210070).

13140234420134 is an equidigital number, since it uses as much as digits as its factorization.

13140234420134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6570117210069.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13140234420134 its reverse (43102443204131), we get a palindrome (56242677624265).

The spelling of 13140234420134 in words is "thirteen trillion, one hundred forty billion, two hundred thirty-four million, four hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 6570117210067 13140234420134