13140240453031 has 4 divisors (see below), whose sum is σ = 13275706849552. Its totient is φ = 13004774056512.

The previous prime is 13140240453019. The next prime is 13140240453049. The reversal of 13140240453031 is 13035404204131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13140240453031 - 2⁴¹ = 10941217197479 is a prime.

It is a super-2 number, since 2×13140240453031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13140240452984 and 13140240453002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13140240453001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67733198115 + ... + 67733198308.

It is an arithmetic number, because the mean of its divisors is an integer number (3318926712388).

Almost surely, 2^{13140240453031} is an apocalyptic number.

13140240453031 is a deficient number, since it is larger than the sum of its proper divisors (135466396521).

13140240453031 is an equidigital number, since it uses as much as digits as its factorization.

13140240453031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135466396520.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13140240453031 its reverse (13035404204131), we get a palindrome (26175644657162).

The spelling of 13140240453031 in words is "thirteen trillion, one hundred forty billion, two hundred forty million, four hundred fifty-three thousand, thirty-one".