Base | Representation |
---|---|
bin | 10011000111110001111… |
… | …011111011101011111001 |
3 | 11122121201121001202202112 |
4 | 103013301323323223321 |
5 | 133012110123422210 |
6 | 2443353155342105 |
7 | 163635512045006 |
oct | 23076173735371 |
9 | 4577647052675 |
10 | 1314024045305 |
11 | 467302353a84 |
12 | 1927bbbb1935 |
13 | 96bb16a4aba |
14 | 47855d208ad |
15 | 242aa207d05 |
hex | 131f1efbaf9 |
1314024045305 has 4 divisors (see below), whose sum is σ = 1576828854372. Its totient is φ = 1051219236240.
The previous prime is 1314024045259. The next prime is 1314024045329. The reversal of 1314024045305 is 5035404204131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 906081245689 + 407942799616 = 951883^2 + 638704^2 .
It is not a de Polignac number, because 1314024045305 - 226 = 1313956936441 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131402404526 + ... + 131402404535.
It is an arithmetic number, because the mean of its divisors is an integer number (394207213593).
Almost surely, 21314024045305 is an apocalyptic number.
It is an amenable number.
1314024045305 is a deficient number, since it is larger than the sum of its proper divisors (262804809067).
1314024045305 is an equidigital number, since it uses as much as digits as its factorization.
1314024045305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262804809066.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 1314024045305 its reverse (5035404204131), we get a palindrome (6349428249436).
The spelling of 1314024045305 in words is "one trillion, three hundred fourteen billion, twenty-four million, forty-five thousand, three hundred five".
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